25x^2-20x=60

Solution for 25x^2-20x=60 equation:

25x^2-20x=60

We move all terms to the left:

25x^2-20x-(60)=0

a = 25; b = -20; c = -60;
Δ = b2-4ac
Δ = -202-4·25·(-60)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-80}{2*25}=\frac{-60}{50}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+80}{2*25}=\frac{100}{50}
=2
$